英译中:The average value of (a-b) +(b-c) over all possibleThe average value of (a-b) +(b-c) over all possible arrangement (a,b,c) of the three numbers (1,4,7) is ____.
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![英译中:The average value of (a-b) +(b-c) over all possibleThe average value of (a-b) +(b-c) over all possible arrangement (a,b,c) of the three numbers (1,4,7) is ____.](/uploads/image/z/14636022-6-2.jpg?t=%E8%8B%B1%E8%AF%91%E4%B8%AD%3AThe+average+value+of+%28a-b%29+%2B%28b-c%29+over+all+possibleThe+average+value+of+%28a-b%29+%2B%28b-c%29+over+all+possible+arrangement+%28a%2Cb%2Cc%29+of+the+three+numbers+%281%2C4%2C7%29+is+____.)
英译中:The average value of (a-b) +(b-c) over all possibleThe average value of (a-b) +(b-c) over all possible arrangement (a,b,c) of the three numbers (1,4,7) is ____.
英译中:The average value of (a-b) +(b-c) over all possible
The average value of (a-b) +(b-c) over all possible arrangement (a,b,c) of the three numbers (1,4,7) is ____.
英译中:The average value of (a-b) +(b-c) over all possibleThe average value of (a-b) +(b-c) over all possible arrangement (a,b,c) of the three numbers (1,4,7) is ____.
在(a-b)+(b-c)这个算式中,将a,b,c三个未知数依次代入1,4,7三个数字(即a=1,b=4,c=7或a=4,b=1,c=7等等(一共六种代入结果)),每次得到算式结果的平均值是多少.
很明显这个结果是0
(笨一点,把算式拆开,(a-b)+(b-c)=a-c,然后a=1,c=7;a=1,c=4;a=4,c=7;a=4,c=1;a=7,c=1;a=7,c=4
全部代入计算,算出所有结果加起来是0,平均值当然还是0)
【我是这么理解的,不敢保证一定对,不好意思……没用英语做过数学题……】