(x²+2x²)-(2x+4)²分解因式急

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(x²+2x²)-(2x+4)²分解因式急
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(x²+2x²)-(2x+4)²分解因式急
(x²+2x²)-(2x+4)²分解因式

(x²+2x²)-(2x+4)²分解因式急
题目应该为:
(x²+2x)²-(2x+4)²
=[(x²+2x)+(2x+4)][(x²+2x-(2x+4)]
=(x²+2x+2x+4)(x²+2x-2x-4)
=(x²+4x+4)(x²-4)
=(x+2)²(x+2)(x-2)