一道二次函数的数学题y=x^2-(2m-1)x+m^2+3m+4(2)设二次函数Y的图象与X轴的交点为A(X1,0)(X2,0),且X1^2+X2^2=5与Y轴的交点为C 它的顶点为M,求直线CM的解析式
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![一道二次函数的数学题y=x^2-(2m-1)x+m^2+3m+4(2)设二次函数Y的图象与X轴的交点为A(X1,0)(X2,0),且X1^2+X2^2=5与Y轴的交点为C 它的顶点为M,求直线CM的解析式](/uploads/image/z/14676817-49-7.jpg?t=%E4%B8%80%E9%81%93%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E7%9A%84%E6%95%B0%E5%AD%A6%E9%A2%98y%3Dx%5E2-%282m-1%29x%2Bm%5E2%2B3m%2B4%EF%BC%882%EF%BC%89%E8%AE%BE%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0Y%E7%9A%84%E5%9B%BE%E8%B1%A1%E4%B8%8EX%E8%BD%B4%E7%9A%84%E4%BA%A4%E7%82%B9%E4%B8%BAA%EF%BC%88X1%2C0%EF%BC%89%EF%BC%88X2%2C0%EF%BC%89%2C%E4%B8%94X1%EF%BC%BE2%EF%BC%8BX2%EF%BC%BE2%EF%BC%9D5%E4%B8%8EY%E8%BD%B4%E7%9A%84%E4%BA%A4%E7%82%B9%E4%B8%BAC+%E5%AE%83%E7%9A%84%E9%A1%B6%E7%82%B9%E4%B8%BAM%2C%E6%B1%82%E7%9B%B4%E7%BA%BFCM%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F)
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