设lim(x->X)f(x)=∞,且x->X时,g(x)的主部是f(x)证明lim(x->X)g(x)=∞,且g(x)~f(x) (x->X).这是道例题,过程里有“由函数极限的局部保号性有g(x)/f(x)>=1/2”为什么g(x)/f(x)>=1/2?这个地方不知道怎么理解证明:由
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![设lim(x->X)f(x)=∞,且x->X时,g(x)的主部是f(x)证明lim(x->X)g(x)=∞,且g(x)~f(x) (x->X).这是道例题,过程里有“由函数极限的局部保号性有g(x)/f(x)>=1/2”为什么g(x)/f(x)>=1/2?这个地方不知道怎么理解证明:由](/uploads/image/z/14680446-6-6.jpg?t=%E8%AE%BElim%28x-%3EX%29f%28x%29%3D%E2%88%9E%2C%E4%B8%94x-%3EX%E6%97%B6%2Cg%28x%29%E7%9A%84%E4%B8%BB%E9%83%A8%E6%98%AFf%28x%29%E8%AF%81%E6%98%8Elim%28x-%3EX%29g%28x%29%3D%E2%88%9E%2C%E4%B8%94g%28x%29%7Ef%28x%29+%28x-%3EX%29.%E8%BF%99%E6%98%AF%E9%81%93%E4%BE%8B%E9%A2%98%2C%E8%BF%87%E7%A8%8B%E9%87%8C%E6%9C%89%E2%80%9C%E7%94%B1%E5%87%BD%E6%95%B0%E6%9E%81%E9%99%90%E7%9A%84%E5%B1%80%E9%83%A8%E4%BF%9D%E5%8F%B7%E6%80%A7%E6%9C%89g%28x%29%2Ff%28x%29%3E%3D1%2F2%E2%80%9D%E4%B8%BA%E4%BB%80%E4%B9%88g%28x%29%2Ff%28x%29%3E%3D1%2F2%3F%E8%BF%99%E4%B8%AA%E5%9C%B0%E6%96%B9%E4%B8%8D%E7%9F%A5%E9%81%93%E6%80%8E%E4%B9%88%E7%90%86%E8%A7%A3%E8%AF%81%E6%98%8E%EF%BC%9A%E7%94%B1)
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