1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^22、xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2第二道题如果答案是(x+1)(y+1)(xy+x+y-1)就不用要过程了.有答案保证+分
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1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^22、xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2第二道题如果答案是(x+1)(y+1)(xy+x+y-1)就不用要过程了.有答案保证+分
1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^2
2、xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2
第二道题如果答案是(x+1)(y+1)(xy+x+y-1)就不用要过程了.
有答案保证+分
1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^22、xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2第二道题如果答案是(x+1)(y+1)(xy+x+y-1)就不用要过程了.有答案保证+分
1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^2
=4(2x^2-x+1)(x^2-2x+3)-[(2x^2-x+1)+(x^2-2x+3)]^2
=4(2x^2-x+1)(x^2-2x+3)-(2x^2-x+1)^2-2(2x^2-x+1)(x^2-2x+3)-(x^2-2x+3)^2
=-(2x^2-x+1)^2+2(2x^2-x+1)(x^2-2x+3)-(x^2-2x+3)^2
=-[(2x^2-x+1)^2-2(2x^2-x+1)(x^2-2x+3)-(x^2-2x+3)^2]
=-[(2x^2-x+1)-(x^2-2x+3)^2]^2
=-(x^2+x-2)^2
=-(x-1)^2(x+2)^2
2、xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2
=x^2y^2+xy+xy+3-2(x+y)-1-(x+y)^2+2(x+y)-1
=x^2y^2+2xy+1-(x+y)^2
=(xy+1)^2-(x+y)^2
=(xy+1+x+y)(xy+1-x-y)
=(x+1)(y+1)(x-1)(y-1)