在三角形ABC中,∠ACB=90°,CD⊥AB于7,AE平分∠BAC交CD于E,交BC于F,EG平行于AB交BC于G,求证:BG=CF
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![在三角形ABC中,∠ACB=90°,CD⊥AB于7,AE平分∠BAC交CD于E,交BC于F,EG平行于AB交BC于G,求证:BG=CF](/uploads/image/z/14760434-2-4.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E2%88%A0ACB%EF%BC%9D90%C2%B0%2CCD%E2%8A%A5AB%E4%BA%8E7%2CAE%E5%B9%B3%E5%88%86%E2%88%A0BAC%E4%BA%A4CD%E4%BA%8EE%2C%E4%BA%A4BC%E4%BA%8EF%2CEG%E5%B9%B3%E8%A1%8C%E4%BA%8EAB%E4%BA%A4BC%E4%BA%8EG%2C%E6%B1%82%E8%AF%81%3ABG%3DCF)
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