y=f(x)中f(1)=-2005/2007,且f(n)=(1-f(n-1))/(1+f(n-1)),f(2006)=?
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y=f(x)中f(1)=-2005/2007,且f(n)=(1-f(n-1))/(1+f(n-1)),f(2006)=?
y=f(x)中f(1)=-2005/2007,且f(n)=(1-f(n-1))/(1+f(n-1)),f(2006)=?
y=f(x)中f(1)=-2005/2007,且f(n)=(1-f(n-1))/(1+f(n-1)),f(2006)=?
f(n)=(1-f(n-1))/(1+f(n-1)),
=2/(1+f(n-1))-1
f(1)=-2005/2007
f(2)=2/(1-2005/2007)-1=2/(2/2007)-1=2007-1=2006
f(3)=2/(1+2006)-1=2/2007-1=-2005/2007=f(1)
...
f(2006)=f(2)=2006
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y=f(x)中f(1)=-2005/2007,且f(n)=(1-f(n-1))/(1+f(n-1)),f(2006)=?
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