a1=2/3,an=-2/3,n=14,求相应等差数列{An}的前N项和Sn
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a1=2/3,an=-2/3,n=14,求相应等差数列{An}的前N项和Sn
a1=2/3,an=-2/3,n=14,求相应等差数列{An}的前N项和Sn
a1=2/3,an=-2/3,n=14,求相应等差数列{An}的前N项和Sn
∵是等差数列
∴d=(a14-a1)/13=-4/39
∴an=a1+(n-1)d=2/3-4(n-1)/39=(30-4n)/39
∴Sn=(a1+an)n/2=(43n-4n^2)/78
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