证明tan(90°-y)=(2cos^3y-cosy)/(siny-2sin^3y)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 09:13:25
证明tan(90°-y)=(2cos^3y-cosy)/(siny-2sin^3y)
x){ٌ< KCt+5m5+uTFqf^i$铬GΆc+J[V}F7F 8Y n5eCs J]CR C OwMy>eœ3YIO[<q-KkL@!July7Ngֳ/.H̳ۼ

证明tan(90°-y)=(2cos^3y-cosy)/(siny-2sin^3y)
证明tan(90°-y)=(2cos^3y-cosy)/(siny-2sin^3y)

证明tan(90°-y)=(2cos^3y-cosy)/(siny-2sin^3y)
证明:∵tan(90°-y)=coty
=cosy/siny
=[cosy*cos(2y)]/[siny*cos(2y)]
=[cosy*(2cos²y-1)]/[siny*(1-2sin²y)] (应用余弦倍角公式)
=(2cos³y-cosy)/(siny-2sin³y)
∴原等式成立.