1.已知a2-a-1=0 且(2a2-3xa2+2)/(a3+2xa2-a)=-93/112 则x=2.已知实数x,y满足方程(x2=2x=3)(3y2=2y=1)=4/3 则x+y=注:字母后的数字是幂
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 10:07:28
![1.已知a2-a-1=0 且(2a2-3xa2+2)/(a3+2xa2-a)=-93/112 则x=2.已知实数x,y满足方程(x2=2x=3)(3y2=2y=1)=4/3 则x+y=注:字母后的数字是幂](/uploads/image/z/14811334-70-4.jpg?t=1.%E5%B7%B2%E7%9F%A5a2-a-1%3D0+%E4%B8%94%282a2-3xa2%2B2%29%2F%28a3%2B2xa2-a%29%3D-93%2F112+%E5%88%99x%3D2.%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B3%E6%96%B9%E7%A8%8B%EF%BC%88x2%3D2x%3D3%29%283y2%3D2y%3D1%29%3D4%2F3+%E5%88%99x%2By%3D%E6%B3%A8%EF%BC%9A%E5%AD%97%E6%AF%8D%E5%90%8E%E7%9A%84%E6%95%B0%E5%AD%97%E6%98%AF%E5%B9%82)
x͐N@_G x1ay| C!4V66R0((ԗawWpz1lf73ԕ-J'sH^^se*2 x3TPUeE=!~LVo _. jȂ
wdudQC%/:"a@U8<^[̪*`U4 3yW,4O$%qFL[;E~qրkIQrnMc_o
e~I
1.已知a2-a-1=0 且(2a2-3xa2+2)/(a3+2xa2-a)=-93/112 则x=2.已知实数x,y满足方程(x2=2x=3)(3y2=2y=1)=4/3 则x+y=注:字母后的数字是幂
1.已知a2-a-1=0 且(2a2-3xa2+2)/(a3+2xa2-a)=-93/112 则x=
2.已知实数x,y满足方程(x2=2x=3)(3y2=2y=1)=4/3 则x+y=
注:字母后的数字是幂
1.已知a2-a-1=0 且(2a2-3xa2+2)/(a3+2xa2-a)=-93/112 则x=2.已知实数x,y满足方程(x2=2x=3)(3y2=2y=1)=4/3 则x+y=注:字母后的数字是幂
老大,你的题目明显不对...
你能不能认真点把题目输入正确啊,我想帮你都帮不了,我连题目都看不懂...