在数列{an}中,a1=2,an+1•an+an+1-2an=0,Σa•an+1
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在数列{an}中,a1=2,an+1•an+an+1-2an=0,Σa•an+1
在数列{an}中,a1=2,an+1•an+an+1-2an=0,Σa•an+1
在数列{an}中,a1=2,an+1•an+an+1-2an=0,Σa•an+1
使n = 2时,m = 1时:(a2)的2 - (A1)2 = A1A3;
所以A3 = -1;
因此n = n> 2时,m = 2的:(一)2 - (A2)2 =(AN-2)(一个2),
(一)2 =(AN-2)(一个2),
这样一个/(一个2)=(AN-2)/一个;
所以a119/a117 = a117/a115 = ...= a3/a1 = -1
所以a119/a1 =(a3/a1)^((117 +1)/ 2)=(-1)^ 59 = -1;
所以A119 = - A1 = -1