若(x-y)/3=(2y-2)/4=(2z+x)/5=1,求x,y,z的值
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若(x-y)/3=(2y-2)/4=(2z+x)/5=1,求x,y,z的值
若(x-y)/3=(2y-2)/4=(2z+x)/5=1,求x,y,z的值
若(x-y)/3=(2y-2)/4=(2z+x)/5=1,求x,y,z的值
答案为:x=6;y=3;z=-1/2
(2y-2)/4=1
y=3
(x-3)/3=1
x=6
(2z+6)/5=1
z=-1/2
由(2y-2)/4=1得y-1/2=1得Y=3.
将Y=3代人(x-y)/3=地X=6.
将X=6代人(2z+x)/5=1得z=-1/2.
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3x+y=2 -y/x+y=123x+y=2 (-y/x)+y=12
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解方程组:2(x +y)-3(x-y)=3;4(x+ y)+ 3(x-y)=15