作业帮谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)
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谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)
谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)
log2(x + 1) = 4 - log2(x + 1)
谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)
log2(x + 1) = 4 - log2(x + 1)
log2(x + 1) = log2(16) - log2(x + 1)
log2(x + 1) = log2[16/(x + 1)]
x+1=16/(x+1)
x+1=4或x+1=-4
所以x=3或x=-5
经检验x=-5是增根,舍去
所以x=3
log2(x+1)=log2(16)- log2(x + 1)
log2(x+1)=log2[16/(X+1)]
X+1=16/(X+1)
X=3或x=-5
log2(x+1)=log2(16)-log2(x+1)
log2(x+1)=log2(16/x+1)
x+1=16/(x+1)
(x+1)(x+1)=16
解得x=3或-5
谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)
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