1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2(2a-4b+c)+(a+3b-c)=?
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1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2(2a-4b+c)+(a+3b-c)=?
1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?
1/2(2a-4b+c)+(a+3b-c)=?
1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2(2a-4b+c)+(a+3b-c)=?
1)1/3[(2a+3b)+1/2a-2/3(6a-5b)]
=1/3*[2a+3b+1/2a-4a+10/3b]
=1/3*[-3/2a+19/3b]
=-1/2a+19/9b
2)1/2(2a-4b+c)+(a+3b-c)
=a-2b+1/2c+a+3b-c
=2a-b-1/2c
1/3[(2a+3b)+1/2a-2/3(6a-5b)]
=1/3(2a+3b+a/2-4a+10b/3)
=1/3(-3a/2+19b/3)
=-a/2+19b/9
1/2(2a-4b+c)+(a+3b-c)
=a-2b+c/2+a+3b-c
=2a+b-c/2