直线y=ax(a>0),与双曲线y=3/x交于A(x1,y1),B(x2,y2)两点,则4x1y2-3x2y1=
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![直线y=ax(a>0),与双曲线y=3/x交于A(x1,y1),B(x2,y2)两点,则4x1y2-3x2y1=](/uploads/image/z/14895676-28-6.jpg?t=%E7%9B%B4%E7%BA%BFy%3Dax%EF%BC%88a%3E0%29%2C%E4%B8%8E%E5%8F%8C%E6%9B%B2%E7%BA%BFy%3D3%2Fx%E4%BA%A4%E4%BA%8EA%EF%BC%88x1%2Cy1%EF%BC%89%2CB%EF%BC%88x2%2Cy2%EF%BC%89%E4%B8%A4%E7%82%B9%2C%E5%88%994x1y2-3x2y1%3D)
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直线y=ax(a>0),与双曲线y=3/x交于A(x1,y1),B(x2,y2)两点,则4x1y2-3x2y1=
直线y=ax(a>0),与双曲线y=3/x交于A(x1,y1),B(x2,y2)两点,则4x1y2-3x2y1=
直线y=ax(a>0),与双曲线y=3/x交于A(x1,y1),B(x2,y2)两点,则4x1y2-3x2y1=
由于两种线都是奇函数所以X1+X2=0.Y1+Y2=0
4(x1y2)-3(x2y1)=-4(x1y1)+3(x1y1)=-x1y1=-3
y=ax代入y=3/x,ax^2-3=0,由韦达定理,x1x2=-3/a
4x1y2-3x2y1=(4y2/x2-3y1/x1)*x1x2=(4a-3a)(-3/a)=-3
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