已知X+Y+Z=22,X+Y=16,X+Z=13,求X,Y.
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已知X+Y+Z=22,X+Y=16,X+Z=13,求X,Y.
已知X+Y+Z=22,X+Y=16,X+Z=13,求X,Y.
已知X+Y+Z=22,X+Y=16,X+Z=13,求X,Y.
设X+Y+Z=22为方程1,X+Y=16为方程2,X+Z=13为方程3
方程1减方程2得Z=6
将Z=6代入方程3得X=7
将X=7代入方程2得Y=9
z=6,x=7,y=9
x=7,y=9,z=6
X+Y+Z=22,X+Y=16,X+Z=13,
y=9
x=7
z=6
X+Y+Z=22 (1) X+Z=13 (2)
(1)-(2)得y=9 X=7
X=7 Y=9
#include
using namespace std;
int main()
{
int x,y,z;
for(x=0;x<22;x++)
for(y=0;y<16;y++)
for(z=0;z<13;z++)
{if(x+y+z==22&&x+y==16&&x+z==13)
cout<
}
答案是7和9
Y=9 ,X=7,Z=6
X+Y+Z=22,X+Y=16,X+Z=13,
x=7 y=9 z=6
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