直线y=-x+4,双曲线y=x/k.k取何值时,直线与双曲线仅有一个交点,设此交点为A,直线与x轴交于点B,O为原点判断三角形OAB的形状,说明理由
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![直线y=-x+4,双曲线y=x/k.k取何值时,直线与双曲线仅有一个交点,设此交点为A,直线与x轴交于点B,O为原点判断三角形OAB的形状,说明理由](/uploads/image/z/14984568-0-8.jpg?t=%E7%9B%B4%E7%BA%BFy%3D-x%2B4%2C%E5%8F%8C%E6%9B%B2%E7%BA%BFy%3Dx%2Fk.k%E5%8F%96%E4%BD%95%E5%80%BC%E6%97%B6%2C%E7%9B%B4%E7%BA%BF%E4%B8%8E%E5%8F%8C%E6%9B%B2%E7%BA%BF%E4%BB%85%E6%9C%89%E4%B8%80%E4%B8%AA%E4%BA%A4%E7%82%B9%2C%E8%AE%BE%E6%AD%A4%E4%BA%A4%E7%82%B9%E4%B8%BAA%2C%E7%9B%B4%E7%BA%BF%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8E%E7%82%B9B%2CO%E4%B8%BA%E5%8E%9F%E7%82%B9%E5%88%A4%E6%96%AD%E4%B8%89%E8%A7%92%E5%BD%A2OAB%E7%9A%84%E5%BD%A2%E7%8A%B6%2C%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
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