log5(1/3) x log36 x log6a=2,求a

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/20 19:42:16
log5(1/3) x log36 x log6a=2,求a
x)O707TP YγM6IEPn)+.zk5O<7]!:'\?'45cڀD ,H=ߵinh]4\q"X1X1TDVdi"hkodj_\g+b

log5(1/3) x log36 x log6a=2,求a
log5(1/3) x log36 x log6a=2,求a

log5(1/3) x log36 x log6a=2,求a
log5(1/3) x log36 x log6a=2 用换底公式,得 [lg(1/3) /lg5]x[lg6/lg3] x [lga/lg6]=2 lg6约去,[-lg3/lg5]x[lga/lg3]=2 lg3约去,lga/lg5=-2 log5a=-2 a=1/25