帮忙化简方程,实在化简不出来了x=r·cosα-vt·sinαy=r·sinα+vt·cosα-1/2g·t^2x^2+y^2=r^2结果是√(grsinα) ·gcosα ·t^3=g^2·t^4/4请问是怎么化简过来的.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/21 02:53:46
![帮忙化简方程,实在化简不出来了x=r·cosα-vt·sinαy=r·sinα+vt·cosα-1/2g·t^2x^2+y^2=r^2结果是√(grsinα) ·gcosα ·t^3=g^2·t^4/4请问是怎么化简过来的.](/uploads/image/z/15061953-57-3.jpg?t=%E5%B8%AE%E5%BF%99%E5%8C%96%E7%AE%80%E6%96%B9%E7%A8%8B%2C%E5%AE%9E%E5%9C%A8%E5%8C%96%E7%AE%80%E4%B8%8D%E5%87%BA%E6%9D%A5%E4%BA%86x%3Dr%C2%B7cos%CE%B1-vt%C2%B7sin%CE%B1y%3Dr%C2%B7sin%CE%B1%2Bvt%C2%B7cos%CE%B1-1%2F2g%C2%B7t%5E2x%5E2%2By%5E2%3Dr%5E2%E7%BB%93%E6%9E%9C%E6%98%AF%E2%88%9A%28grsin%CE%B1%29+%C2%B7gcos%CE%B1+%C2%B7t%5E3%3Dg%5E2%C2%B7t%5E4%2F4%E8%AF%B7%E9%97%AE%E6%98%AF%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80%E8%BF%87%E6%9D%A5%E7%9A%84.)
帮忙化简方程,实在化简不出来了x=r·cosα-vt·sinαy=r·sinα+vt·cosα-1/2g·t^2x^2+y^2=r^2结果是√(grsinα) ·gcosα ·t^3=g^2·t^4/4请问是怎么化简过来的.
帮忙化简方程,实在化简不出来了
x=r·cosα-vt·sinα
y=r·sinα+vt·cosα-1/2g·t^2
x^2+y^2=r^2
结果是√(grsinα) ·gcosα ·t^3=g^2·t^4/4
请问是怎么化简过来的.
帮忙化简方程,实在化简不出来了x=r·cosα-vt·sinαy=r·sinα+vt·cosα-1/2g·t^2x^2+y^2=r^2结果是√(grsinα) ·gcosα ·t^3=g^2·t^4/4请问是怎么化简过来的.
x=r·cosα-vt·sinα (^表示平方,^4表示4次方)
y=r·sinα+vt·cosα-1/2g·t^ ==>y+1/2g·t^=r·sinα+vt·cosα
x^+(y+1/2g·t^)^=(r·cosα-vt·sinα )^+(r·sinα+vt·cosα)^=r^+(vt)^
x^+y^+g*t^*y+g^t^4/4=r^+(vt)^
gt^y=(vt)^-g^t^4/4
y=(vt)^/gt^-gt^/4
代入x^+y^=r^ 可得x值
x^2=r^2cos^2a-2rvtcosasina+v^2t^2sin^2a
y^2=r^2sin^2a+v^2t^2cos^2a+1/4g^2t^4+2rvtsinacosa-rgt^2sina-vgt^3cosa
x^2+y^2=r^2+v^2t^2+1/4g^2t^4-rgt^2sina-vgt^3cosa=r^2
从而得出1/4g^2t^4=rgt^2sina+vgt^3cosa-v^2t^2
只能算出这么多了
能否给出原题,你算到的这部分无法化出结果。