设f‘’(x)<0,a,b>0,证f(a+b)+f(0)<f(a)+f(b)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/14 07:43:11
![设f‘’(x)<0,a,b>0,证f(a+b)+f(0)<f(a)+f(b)](/uploads/image/z/15062179-67-9.jpg?t=%E8%AE%BEf%E2%80%98%E2%80%99%28x%29%EF%BC%9C0%2Ca%2Cb%EF%BC%9E0%2C%E8%AF%81f%28a%2Bb%29%2Bf%280%29%EF%BC%9Cf%28a%29%2Bf%28b%29)
x){n_ڣfjTh3@'Q'y:/7i$j'iji<;I&H<v6؉,iON0TiOh h!Iec=p: 1f 9[y
设f‘’(x)<0,a,b>0,证f(a+b)+f(0)<f(a)+f(b)
设f‘’(x)<0,a,b>0,证f(a+b)+f(0)<f(a)+f(b)
设f‘’(x)<0,a,b>0,证f(a+b)+f(0)<f(a)+f(b)
f‘’(x)<0
那么当x1 [f(a+b)-f(a)]/b
f(b)-f(0)>f(a+b)-f(a)
得到:f(a+b)+f(0)<f(a)+f(b)