设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的...设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的必要不充分条件,求实数a的取值范围
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设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的...设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的必要不充分条件,求实数a的取值范围
设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的...
设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的必要不充分条件,求实数a的取值范围
设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的...设函数-x^2+7x-12>0的解集为A.(1)求集合A (2)设p:x属于A,q:x>a.且q是p的必要不充分条件,求实数a的取值范围
A的集合为,3
1) 3
a》=4
(1)
-(x-3)(x-4)>0
(x-3)(x-4)<0
3
x>a是x属于A的必要不充分条件,即x属于A=>x>a
因为A={x|3
(-x+3)(x+4)>0
得:3
即是由P可推出q,但q不能推出P
所以a<=3
集合A是X<3并X>4,(2)a取值范围是3《a<4
(1)由-x^2+7x-12>0,得x^2-7x+12<0,得(x-3)(x-4)<0 得:3
即A={x|3