2(y+2)-3(4y-1)=9(1-y)一元一次怎么算?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 17:36:59
2(y+2)-3(4y-1)=9(1-y)一元一次怎么算?
x)3Ҩ6505Դ0ԭ|ik3|f᳆';;noTOz;*٠`Tmk$m-u-+L] 56ֵT5/.H̳ cQ

2(y+2)-3(4y-1)=9(1-y)一元一次怎么算?
2(y+2)-3(4y-1)=9(1-y)一元一次怎么算?

2(y+2)-3(4y-1)=9(1-y)一元一次怎么算?
2(y+2)-3(4y-1)=9(1-y) 2y+4-12y+3=9-9y 12y-2y-9y=4+3-9 y=-2