已知1/x-1/y=5,求(2x+4xy-2y)/x-3xy-y)的值
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已知1/x-1/y=5,求(2x+4xy-2y)/x-3xy-y)的值
已知1/x-1/y=5,求(2x+4xy-2y)/x-3xy-y)的值
已知1/x-1/y=5,求(2x+4xy-2y)/x-3xy-y)的值
1/x-1/y=5
(y-x)/xy=5
y-x=5xy
所以x-y=-5xy
原式=[2(x-y)+4xy]/[(x-y)-3xy]
=[2(-5xy)+4xy]/[(-5xy)-3xy]
=-6xy/(-8xy)
=3/4
(2x+4xy-2y)/x-3xy-y)分子分母都除以xy得
=(2/y+4-2/x)/(1/y-3-1/x)
=(4-10)/(-3-5)
=-6/-8
=3/4