a=-(-2)^2,b=-(-3)^2,c=-(-4^2).则-[-a-(b+c)]=
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a=-(-2)^2,b=-(-3)^2,c=-(-4^2).则-[-a-(b+c)]=
a=-(-2)^2,b=-(-3)^2,c=-(-4^2).
则-[-a-(b+c)]=
a=-(-2)^2,b=-(-3)^2,c=-(-4^2).则-[-a-(b+c)]=
则-[-a-(b+c)]
=a+b+c
=-4-9+16
=3;
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a=-(-2)^2=-4,b=-(-3)^2=-9,c=-(-4^2)=16
所以
原式=a+b+c=-4-9+16=3