a²+b²+c²=ab+bc+ca 求(3a+2b+c)²º¹²
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a²+b²+c²=ab+bc+ca 求(3a+2b+c)²º¹²
a²+b²+c²=ab+bc+ca 求(3a+2b+c)²º¹²
a²+b²+c²=ab+bc+ca 求(3a+2b+c)²º¹²
解
a²+b²+c²=ab+bc+ca
2a²+2b²+2c²-2ab-2bc-2ca=0
(a²-2ab+b²)+(a²-2ac+c²)+(b²-2bc+c²)=0
(a-b)²+(a-c)²+(b-c)²=0
a-b=0 a-c=0 b-c=0
a=b=c