a1=1,an+1=an/2 + 1/an,求证对于一切大于1的自然数n,数2/根号下（a²n-2）都是自然数

数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列an中,a1=3,an+1=an/2an+1,则an=? 数列{an},a1=1,2a(n+1)=an +1,求通项an? 数列{an}满足a1=a,an+1=1+1/an.若3/2 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知{an}满足a1=1,a(n+1)=2an+2,求an 已知数列{an},A1=1 A(n+1)=2an/an+2 求a5 a(n+1)=2an/3an+4,a1=1/4,求an 数列{an},a1=3,an*a(n+1)=(1/2)^n,求an 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列｛an｝,a1=2,4a(n+1)-an=2,求通项an 数列[An]满足a1=2,a（n+1）=3an-2 求an 在数列{an}中.a1=3且a(n+1)=an^2,求an 已知数列｛an｝中,a(n+1)=an+2^n,a1=3,求an 1.a1=1 an=a1+2a2+.(n-1)an-1求an2.an+a（n+1）=1/2,a1=1,求an 已知数列an满足条件a1=-2 a（n+1）=2an/(1-an) 则an= 已知数列{an},a1=1,a(n+1)=an^2+an+1,求通项公式an