高中数学题sinπ/12·cosπ/12
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高中数学题sinπ/12·cosπ/12
高中数学题sinπ/12·cosπ/12
高中数学题sinπ/12·cosπ/12
二倍角的正弦公式,
sinπ/12·cosπ/12
=(1/2)sin(π/6)
=(1/2)(1/2)
=1/4
sin(π-a)-cos(π a) =sina cosa =√2(sina π/4)=√2/4 (sina π/4)=1/4 sin 0
sinπ/12*cosπ/12=1/2*sin(2*π/12)=1/2*sinπ/6=1/4
这类题目就是要对正余弦函数的性质熟悉,根据具体的表达式利用相应的变换公式来简化原式,从而求得结果,本题利用sin(2x)=2(sinx)*(cosx)
原式=sin{(pi/12)*2} / 2
=sin(pi/6) / 2
=1/4
原式=1/2sinπ/6=1/2·1/2=1/4
高中数学题sinπ/12·cosπ/12
(sinπ/24)(cosπ/24)(cosπ/12)
(sinπ/24)(cosπ/24)(cosπ/12)
sinπ/12*cosπ/12=?
求值:sin(π/12)+cos(π/12)
sin(π/12)-cos(π/12)=
cos*π/12—sin*π/12
cosπ/12乘以sinπ/12
计算cosπ/12*sinπ/12
求算一道高中数学题三角函数题,sin(1/6π-a)=1/3,则,cos(2/3π +2a)=?
【高中数学题】【在线等】【必采纳】已知函数f(x)=cos(2x-5π/3)+2sin(x-π/4)sin(x+π/4)(1)求函数的最小正周期和对称轴方程(2)求函数f(x)在区间[-π/12,π/2]值域
【高中数学题】【在线等】【必采纳】已知函数f(x)=cos(2x-5π/3)+2sin(x-π/4)sin(x+π/4)(1)求函数最小正周期和对称轴方程(2)求函数f(x)在区间[-π/12,π/2]上的值域
一道高中数学题 三角恒等变换已知cos(π/4-α)=3/5,sin(5π/4+β)=-12/13, α∈(π/4,3π/4) β∈(0,π/4)求sin(α+β)的值?
(cosπ/12-sinπ/12)*(COSπ/12+sinπ/12)等于
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)等于
(cosπ/12-sinπ/12)(cosπ/12+sinπ/12)的值为
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(sinπ/12+cosπ/12)(sinπ/12-cosπ/12)=