若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/06 14:14:28
![若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0](/uploads/image/z/15213797-53-7.jpg?t=%E8%8B%A5sin%283%E6%B4%BE%2F4%2B%CE%B1%29%3D5%2F13%2Ccos%28%E6%B4%BE%2F4%EF%BC%8D%CE%B1%29%EF%BC%9D3%2F5%2C0)
x){ѽ83Oٖ}&6jښ$k
3XT&HT-v6dZ\g5y:ygs:mzg>X]S^_lzaMtmҴ5I6:^
Ѵ
tZqi5BF]9F@v,d@] b(x`pPBOOkxټƩO4r%!L-BH{m UE\E#|7!Ee] QX[<>H2 e
若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0
若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0
若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0
0
哪里有β?
应该是cos(π/4-β)=3/5
3π/4<3π/4+α<π
所以cos(3π/4+α)<0
sin²(3π/4+α)+cos²(3π/4+α)=1
所以cos(3π/4+α)=-12/13
π/4<β<3π/4
-π/2<π/4-β<0
所以sin(π/4-β)<0
sin²(π/...
全部展开
哪里有β?
应该是cos(π/4-β)=3/5
3π/4<3π/4+α<π
所以cos(3π/4+α)<0
sin²(3π/4+α)+cos²(3π/4+α)=1
所以cos(3π/4+α)=-12/13
π/4<β<3π/4
-π/2<π/4-β<0
所以sin(π/4-β)<0
sin²(π/4-β)+cos²(π/4-β)=1
sin(π/4-β)=-4/5
cos(α+β)
=sin[π/2-(α+β)]
=sin[(3π/4+α)-(π/4-β)]
=sin(3π/4+α)cos(π/4-β)-cos(3π/4+α)sin(π/4-β)
=-33/65
收起
已知sinx=-5/13,x属于(派,3派/2),求sin(x-派/4)
若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0
若sin(3派/4+α)=5/13,cos(派/4-α)=3/5,0
若sin(3派/4+α)=5/13,cos(派/4-β)=3/5,0
已知sin (α+派/3)+sinα=-4根号3/5,-派/2
若cos(α+派)=3/5,派≦α≦2派,则sin(-α-2派)的值
sin(a+b)=-3/5,sin(b-派/4)=12/13,ab属于(3派/4,派)求cos(a+派/4)
已知 Sin(X+ 派/6)=1/4求 Sin(5/6派 - X)+Sin^2 (派/3 -X)
若a属于(派,2派),且sin(3派/2+a)=4/5,则tana/2等于
已知sinα=4分之5,求下列三角函数值 sin(-α) sin(派-α) sin(派+α) sin(2派-α)
已知sin(4分之派-a)=5分之3,求sin(a-13派/4)的值.
已知a,b∈(3派÷4,派),sin(a+b)=-5分之3,sin(b-4分之派),求cos(a+4分之派)
sin(派-a)=4/5.且派/5
已知sin α=3/5,α属于(派/2,派),cos β=-(5/13),β属于(派,3派/2),求cos(α-β),sin(α+β)
已知a,b属于(3派/4,派),sin(a+b)=-3/5,sin(b-派/4)=12/13则cos(a+派/4)=
已知a,b属于(3/4派,派),sin(a+b)=-3/5,sin(b-派/4)=12/13,则cos(a+派/4)=多少
已知sin(a-b)=5/13,sin(a+b)=-4/5,且a-b属于(2分之派,派),a+b属于(2分之3派,2派),求cos2b,sin2a的值
已知tan(a+5派)=m,化简:[sin(a-3派)+cos(派-a)]/[sin(-a)-cos(派+a)]