(x+3)平方=x+3方程解 已知:a(1)=x,a(n+1)=1-[1/a(n)],(n=1,2,3...),试用x表示a(2009)+a(2010)+a(2011)已知:a(1)=x,a(n+1)=1-[1/a(n)],(n=1,2,3...),试用x表示a(2009)+a(2010)+a(2011);并求x=5时的值.
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![(x+3)平方=x+3方程解 已知:a(1)=x,a(n+1)=1-[1/a(n)],(n=1,2,3...),试用x表示a(2009)+a(2010)+a(2011)已知:a(1)=x,a(n+1)=1-[1/a(n)],(n=1,2,3...),试用x表示a(2009)+a(2010)+a(2011);并求x=5时的值.](/uploads/image/z/15214311-63-1.jpg?t=%28x%2B3%29%E5%B9%B3%E6%96%B9%3Dx%2B3%E6%96%B9%E7%A8%8B%E8%A7%A3+%E5%B7%B2%E7%9F%A5%EF%BC%9Aa%281%29%3Dx%2Ca%28n%2B1%29%3D1-%5B1%2Fa%28n%29%5D%2C%28n%3D1%2C2%2C3...%29%2C%E8%AF%95%E7%94%A8x%E8%A1%A8%E7%A4%BAa%282009%29%2Ba%282010%29%2Ba%282011%29%E5%B7%B2%E7%9F%A5%EF%BC%9Aa%281%29%3Dx%2Ca%28n%2B1%29%3D1-%5B1%2Fa%28n%29%5D%2C%28n%3D1%2C2%2C3...%29%2C%E8%AF%95%E7%94%A8x%E8%A1%A8%E7%A4%BAa%282009%29%2Ba%282010%29%2Ba%282011%29%EF%BC%9B%E5%B9%B6%E6%B1%82x%3D5%E6%97%B6%E7%9A%84%E5%80%BC.)
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