(1+√3i)³=-8
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(1+√3i)³=-8
(1+√3i)³=-8
(1+√3i)³=-8
1+√3i=2(cos60°+isin60°),
由狄莫佛定理,(1+√3i)^3=2^3*(cos180°+isin180°)=-8.
解2:(1+√3i)^3
=1+3√3i+3(√3i)^2+(√3i)^3
=1+3√3i-9-3√3i
=-8.