已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=

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已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
x){}K4*4m537Thj$9F)-ӎiF&PCxH@@6TCr cA&$Slj&v6C"0pX.i@P3!.+1400?Qe4j$ف 

已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=

已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=已知f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4,则f(2014)=
f(x)=(sinπx/4)^2-(cosπx/4)^2-2(sinπx/4)*cosπx/4
=-cos(πx/2)-sin(πx/2)
f(2014)=-cos(1007π)-sin(1007π)=-cos(π)-sin(π)=1