已知α,β为锐角,3sin^2α+2sin^2β=1 3sin2α-2sin2β=0 ,求α+2β,请写出具体步骤,

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已知α,β为锐角,3sin^2α+2sin^2β=1 3sin2α-2sin2β=0 ,求α+2β,请写出具体步骤,
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已知α,β为锐角,3sin^2α+2sin^2β=1 3sin2α-2sin2β=0 ,求α+2β,请写出具体步骤,
已知α,β为锐角,3sin^2α+2sin^2β=1 3sin2α-2sin2β=0 ,求α+2β,请写出具体步骤,

已知α,β为锐角,3sin^2α+2sin^2β=1 3sin2α-2sin2β=0 ,求α+2β,请写出具体步骤,
cos(α+2β) =cosαcos2β-sinαsin2β =cosα(1-2(sinβ)^2)-sinαsin2β =cosα(3(sinα)^2)-sinα(3*sin(2α)/2) =3sin(2α)sinα/2-3sin(2α)*sinα/2 =0 又α,β为锐角,所以0