2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ]
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2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ]
2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ]
2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ]
(sin^2 x +cos^2 x)^2 -2(sinxcosx)^2=1/2
1-2(sinxcosx)^2=1
sin2x=...
又x∈[-pi,pi]
所以x=...
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