已知复数(1+i)3 (a-i)2/√2(a+3i)2的模是2/3,求a
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已知复数(1+i)3 (a-i)2/√2(a+3i)2的模是2/3,求a
已知复数(1+i)3 (a-i)2/√2(a+3i)2的模是2/3,求a
已知复数(1+i)3 (a-i)2/√2(a+3i)2的模是2/3,求a
这个复数的模=|(1+i)³|(a-i)²|/√2|(a+3i)²|=2/3,即:
2√2(a²+1)=(2/3)√2(a²+9)
解得:a=±√3.