f(x,y)=3xy/x^2+y^2 lim(x→0)(lim(y→0)f(x,y))
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 20:59:34
xRJ@A$m
&.Jd-&ZmUmS*̤$m*t57{9h܊$SԳTP>2u}k(Ҍʘ'j˛ʟgBNKO ~f.-UOX{J#&kcdžuIb^ЯO1f=VZ{CLB,$C_'쩺21&^4JsS7ޞd@G`r%)6g
47_XTtʈKq܊ϖ5~B[`KvRk1zm|uN'd>hҌ J`uhNjl"āevJ@pWXYS
K9?|I/@
f(x,y)=3xy/x^2+y^2 lim(x→0)(lim(y→0)f(x,y))
f(x,y)=3xy/x^2+y^2 lim(x→0)(lim(y→0)f(x,y))
f(x,y)=3xy/x^2+y^2 lim(x→0)(lim(y→0)f(x,y))
=0.
因为是先后取极限,而不是同时取极限.
当对y取极限时,x暂时看作常数.则lim(y→0)f(x,y)=3x×0/x^2+0^2=0.
再对x取极限仍得0.
如果是同时对x和y取极限,则极限不存在:
令y=k·x,k为常数,则
lim(x→0,y→0)=3kx²/(1+k²)x²
=3k/(1+k²)
当k取不同的值时,这个结果也会不同.也就是说不会得到一个确定的值.所以在这种情况下极限不存在.
f(xy,x-y)=x^2+3xy+y^2,则f(x,y)=?
f(x+y)=f(x)+f(y)+2xy
f(xy,x-y)=x^2+y^2+xy;f(x,y)/∂x;f(x,y)/∂y
f(x+y,x-y)=(x^2-y^2)/2xy,求f(x,y)!
f(x+y,x-y)=2xy(x-y),求f(x,y)
f(xy,x-y)=x^2-xy+y^2.求f(x,y)
高数题!f(x,y)=x^3-2xy+3y^2,求f(x+y,x-y).要借题步骤
f(x,y)=x^2+xy+y^2-3x-6y的极值
y'=-2xy;求f(x).
函数f(xy,x+y)=x^2+xy+y^2,则df(x,y)=?
设f(x+y,x-y)=x^2+xy,求f(x,y)
f(x^2-y^2,x-y)=x+y+x^2-xy,求f'(x,y)对y求导
对任意的实数x,y,f(x+y)=2f(y)+x^2+2xy-y^2+3x-3y,求f(x)
lx+2l+[y+3]平方=06xy平方-[3x平方y-{2x平方y-xy}]
设f(x+y,xy)=x^2+y^2-xy,则(∂f(x,y))/∂y=
f(2x+y,2y+x)=xy,求f(x,y)
设f(x+y,xy)=x^2+y^2,则f(x,y)
f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式