急!急!急!已知x²-2x-1=0,求(2x-1)²-x(x+4)+(x-2)(x+2)的值
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急!急!急!已知x²-2x-1=0,求(2x-1)²-x(x+4)+(x-2)(x+2)的值
急!急!急!已知x²-2x-1=0,求(2x-1)²-x(x+4)+(x-2)(x+2)的值
急!急!急!已知x²-2x-1=0,求(2x-1)²-x(x+4)+(x-2)(x+2)的值
原式
=4x平方-4x+1-x平方-4x+x平方-4
=4x平方-8x-3
=4(x平方-2x-1)+4-3
=4-3
=1