3、已知x分之1+y分之1=5,求x-2xy+y分之2x+3xy+2y的值4、先化简,再求值[(x²-1分之3x+4)-(x-1分之2)]÷x²-2x+1分之x+2 ,其中x是不等式组{x+4>0,2x+5<1的整数解
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![3、已知x分之1+y分之1=5,求x-2xy+y分之2x+3xy+2y的值4、先化简,再求值[(x²-1分之3x+4)-(x-1分之2)]÷x²-2x+1分之x+2 ,其中x是不等式组{x+4>0,2x+5<1的整数解](/uploads/image/z/15258839-23-9.jpg?t=3%E3%80%81%E5%B7%B2%E7%9F%A5x%E5%88%86%E4%B9%8B1%2By%E5%88%86%E4%B9%8B1%3D5%2C%E6%B1%82x-2xy%2By%E5%88%86%E4%B9%8B2x%2B3xy%2B2y%E7%9A%84%E5%80%BC4%E3%80%81%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BC%5B%EF%BC%88x%26%23178%3B-1%E5%88%86%E4%B9%8B3x%EF%BC%8B4%EF%BC%89-%EF%BC%88x-1%E5%88%86%E4%B9%8B2%EF%BC%89%5D%C3%B7x%26%23178%3B-2x%EF%BC%8B1%E5%88%86%E4%B9%8Bx%EF%BC%8B2+%2C%E5%85%B6%E4%B8%ADx%E6%98%AF%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84%7Bx%2B4%EF%BC%9E0%2C2x%2B5%EF%BC%9C1%E7%9A%84%E6%95%B4%E6%95%B0%E8%A7%A3)
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