作业帮tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)急用啊
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![tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)急用啊](/uploads/image/z/1535073-33-3.jpg?t=tan2a%3D-2%E6%A0%B9%E5%8F%B72%2C2a%E5%B1%9E%E4%BA%8E%2890%60%2C180%60%29%2C%E6%B1%82+%5B2cos%5E2%28a%2F2%29-sina-1%5D%2F%E6%A0%B9%E5%8F%B72sin%28a%2B45%60%29%E6%80%A5%E7%94%A8%E5%95%8A)
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tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)急用啊
tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)
急用啊
tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)急用啊
tan2a=-2√2 (cos2a) ^2=1/(1+(tan2a)^2)=1/9
cos2a=-1/3
(sina)^2=(1-cosa)/2=2/3 sina=√2/√3=√6/3
(cosa)^2=(1+cosa)/2=1/3 cosa=1/√3=√3/3
2(cos(a/2))^2-1=cosa
sin(a+45)=(√2/2)(√6+√3)/3
[2(cos(a/2))^2-sina-1]/[√2sin(a+45)]= [(√3-√6)/3]/(√6+√3)/3=-(√6-√3)^2/3=-3+2√2
tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)急用啊
tan2a=-2根号2,2a属于(90`,180`),求[cos^2(a/2)-sina-1]/根号2sin(a+45`)
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