已知a=2,b=-1,求1+(a²-b²/a²-ab)除以1/a
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已知a=2,b=-1,求1+(a²-b²/a²-ab)除以1/a
已知a=2,b=-1,求1+(a²-b²/a²-ab)除以1/a
已知a=2,b=-1,求1+(a²-b²/a²-ab)除以1/a
=1+(5/6)×2
=8/3
1+(a²-b²/a²-ab)除以1/a
=1+(a²-b²/a²-ab)*a
=1+(a-b)(a+b)/(a-b)
=1+(a+b)
=1+2-1
=2
二分之二十七