若多项式x^2-(a+5)x+5a-1能够分解成两个一次因式(a+b)(x+c)的乘积,求a的值(5a-1)*4中4是哪来的?
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![若多项式x^2-(a+5)x+5a-1能够分解成两个一次因式(a+b)(x+c)的乘积,求a的值(5a-1)*4中4是哪来的?](/uploads/image/z/1573967-47-7.jpg?t=%E8%8B%A5%E5%A4%9A%E9%A1%B9%E5%BC%8Fx%5E2-%28a%2B5%29x%2B5a-1%E8%83%BD%E5%A4%9F%E5%88%86%E8%A7%A3%E6%88%90%E4%B8%A4%E4%B8%AA%E4%B8%80%E6%AC%A1%E5%9B%A0%E5%BC%8F%28a%2Bb%29%28x%2Bc%29%E7%9A%84%E4%B9%98%E7%A7%AF%2C%E6%B1%82a%E7%9A%84%E5%80%BC%285a-1%29%EF%BC%8A4%E4%B8%AD4%E6%98%AF%E5%93%AA%E6%9D%A5%E7%9A%84%EF%BC%9F)
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