x-3/2=2,则4x²-12x+10=

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 15:50:18
x-3/2=2,则4x²-12x+10=
x)575y1ӤBMZШB&H~ a^,_tCTٓK^tgv>_tt5Pږ&&`A,m :^n9X:L{d{:m 젎snyG';g4YF@i[dS1DvH'T5Gsl΁] ;{c֥O'= .,^G F1

x-3/2=2,则4x²-12x+10=
x-3/2=2,则4x²-12x+10=

x-3/2=2,则4x²-12x+10=
解 将x-3/2=2两边平方可得
x²-3x+9/4=4
4x²-12x+9=16
所以4x²-12x+10=17
(安化老九)

x-3/2=2, 两边乘以2得:2x-3=4, x=7/2
4x²-12x+10=(2x)²-12x+9+1=(2x-3)²+1=(7-3)²+1=16+1=17

17

x=7/2
带入后式可得 4x²-12x+10=17