x-3/2=2,则4x²-12x+10=

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x-3/2=2,则4x²-12x+10=
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x-3/2=2,则4x²-12x+10=
x-3/2=2,则4x²-12x+10=

x-3/2=2,则4x²-12x+10=
解 将x-3/2=2两边平方可得
x²-3x+9/4=4
4x²-12x+9=16
所以4x²-12x+10=17
(安化老九)

x-3/2=2, 两边乘以2得:2x-3=4, x=7/2
4x²-12x+10=(2x)²-12x+9+1=(2x-3)²+1=(7-3)²+1=16+1=17

17

x=7/2
带入后式可得 4x²-12x+10=17