已知|x+y-3|+(2x-3y+5)²=0,求x+y的平方根
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已知|x+y-3|+(2x-3y+5)²=0,求x+y的平方根
已知|x+y-3|+(2x-3y+5)²=0,求x+y的平方根
已知|x+y-3|+(2x-3y+5)²=0,求x+y的平方根
|x+y-3|+(2x-3y+5)²=0
|x+y-3|=0
(2x-3y+5)²=0
x+y-3=0
2x-3y+5=0
x+y=3
2x-3y=-5
3x+3y=9
2x-3y=-5
3x+2x=9-5
x=4/5
y=3-x
y=3-4/5
y=11/5
x+y=4/5+11/5=3
x+y的平方根=±根号3
x+y-3=0;(1)
2x-3y+5=0;(2)
(1)×2-(2)得:
5y-11=0;
y=11/5;
x=4/5;
x+y的平方根=√3;
|x+y-3|+(2x-3y+5)²=0
x+y-3=0 1
2x-3y+5=0 2
1式*2-2式得
5y-11=0
y=11/5
1式*3+2式得
5x-4=0
x=4/5
√(x+y)=√(11/5+4/5)=√3
由非负数的和为零得
x+y-3=0 2x-3y+5=0 联立解得x=4/5 y=11/5
故√x+y=√3
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解;由题意知道:x+y-3=0,2x-3y+5=0.则,x=4/5,y=11/5
则x+y=3,即(x+y)^1/2=3^1/3,即根号3
x+y=3
(x+y)的平方根=±√3=±1.7320508075688772935274463415059......
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