如图,在等边三角形ABC中,E,D分别为AC,BC上的点,AE=CD,AD交BE于点P,BQ垂直AD于点Q,是证明BP=2PQ如图,在等边三角形ED分别为AC,BC上的点,AE=CD,AD交BE于点P,BQ垂直AD于点Q,是证明BP=2PQ
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/06 17:35:34
![如图,在等边三角形ABC中,E,D分别为AC,BC上的点,AE=CD,AD交BE于点P,BQ垂直AD于点Q,是证明BP=2PQ如图,在等边三角形ED分别为AC,BC上的点,AE=CD,AD交BE于点P,BQ垂直AD于点Q,是证明BP=2PQ](/uploads/image/z/1600154-26-4.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CE%2CD%E5%88%86%E5%88%AB%E4%B8%BAAC%2CBC%E4%B8%8A%E7%9A%84%E7%82%B9%2CAE%3DCD%2CAD%E4%BA%A4BE%E4%BA%8E%E7%82%B9P%2CBQ%E5%9E%82%E7%9B%B4AD%E4%BA%8E%E7%82%B9Q%2C%E6%98%AF%E8%AF%81%E6%98%8EBP%3D2PQ%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ED%E5%88%86%E5%88%AB%E4%B8%BAAC%2CBC%E4%B8%8A%E7%9A%84%E7%82%B9%2CAE%3DCD%2CAD%E4%BA%A4BE%E4%BA%8E%E7%82%B9P%2CBQ%E5%9E%82%E7%9B%B4AD%E4%BA%8E%E7%82%B9Q%2C%E6%98%AF%E8%AF%81%E6%98%8EBP%3D2PQ)
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