log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/24 10:53:26
xN@_ed1ƍQ/ H6
̴}Oֺ?9͘!I%C.ihD24-+HTޫ`TJek<8ժe=%[;CL>,M|E\D^]܊ѳqEWXx'M$i
5P^볰ɒ^z1\v/_,~I7M xEtл#P
Ӹ-<6E/s@T*J-LT
;fvf_f2Yj|U̻idþjjgr
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
这一题 是对数的定义问题,log2(2)的数学定义就是底数2的多少次方等于真数2,很显然是1了,那么依照这个思路你可以得到log5(1)=0,log1/3(1/27)=3log1/3(1/3)=3,3^log3(5)=5,3^-log3(2)=1/2,那么本题的结果为1+0-3+5^2+1/2=1+0-3+25+0.5=23.5.总体而言本题考的就是概念的理解.
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
1、计算log5^35+2log1/2^根号2-log5^1/50-log5^14 2、已知log3^7=a,log2^3=b,求log21^28
比较log2^(1/3),log1/3^2,log5^2的大小速度,谢了!
计算Log5 35+2log1/2√2-log5 1/50-log5 14急急急!!!
Log5^35+2log1/2^√2-log5^1/50-log5^14求值
一道高一数学题对数log2,详见补充已知log2[log1/2(log2^x)]=log3[log1/3(log3^y)]=log5[log1/5(log5^z)]=0,试比较x,y,z的大小?
lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) )
诺log2[log1/2(log2x)]=log3[log1/3(log3y)]=比log5[log1/5(log5z)]=o,较x,y,z大小关于2,3,5,1/2,1/3,1/5,都是下标,因为不会打.
已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)]=0.求x2+y^3-z^5的值
对数 log5(35)+2log1/2( 根号2)-log5(1/50)-log5(14)log5(35)+2log1/2( 根号2)-log5(1/50)-log5(14)
怎样计算(log2)^2+(log5)^2+(2*log2)*log5
log2(log5 x)=-1
(log5)^2+(log2)(log50)=?
(log5)^2+log2·log50
(log2)^2+(log5)^2+log2*log25
log的一道数学题log3 1/64×log4 √5×log1/25 27 √5是根号下5 ×是乘号=log3 2^(-6) ×log2^2 5^(1/2) ×log5^(-2) 3^3=[(-6)×log3 2] ×[(1/2)×(1/2)×log2 5] ×[(-1/2)×3×log5 3]这个是怎么转换的 底数也能放前面吗比如log2^
2^(1/2log2 3)+(1/25)^log5 3=
求值:log2∧5×log5∧1/2