1.若|(X-1)/(2X-3)|+[(3Y+1)/Y+4]^2=0.求代数式:3/2X+1-2/3Y-1.此题答案为2.2.已知A,B,C满足1/A+1/B+1/C不等于0,A(1/B+1/C)+B(1/A+1/C)+C(1/A+1/B)=-3,求A+B+C的值.此题答案为0.
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![1.若|(X-1)/(2X-3)|+[(3Y+1)/Y+4]^2=0.求代数式:3/2X+1-2/3Y-1.此题答案为2.2.已知A,B,C满足1/A+1/B+1/C不等于0,A(1/B+1/C)+B(1/A+1/C)+C(1/A+1/B)=-3,求A+B+C的值.此题答案为0.](/uploads/image/z/1602706-58-6.jpg?t=1.%E8%8B%A5%7C%28X-1%29%2F%282X-3%29%7C%2B%5B%283Y%2B1%29%2FY%2B4%5D%5E2%3D0.%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%9A3%2F2X%2B1-2%2F3Y-1.%E6%AD%A4%E9%A2%98%E7%AD%94%E6%A1%88%E4%B8%BA2.2.%E5%B7%B2%E7%9F%A5A%2CB%2CC%E6%BB%A1%E8%B6%B31%2FA%2B1%2FB%2B1%2FC%E4%B8%8D%E7%AD%89%E4%BA%8E0%2CA%281%2FB%2B1%2FC%29%2BB%281%2FA%2B1%2FC%29%2BC%281%2FA%2B1%2FB%29%3D-3%2C%E6%B1%82A%2BB%2BC%E7%9A%84%E5%80%BC.%E6%AD%A4%E9%A2%98%E7%AD%94%E6%A1%88%E4%B8%BA0.)
1.若|(X-1)/(2X-3)|+[(3Y+1)/Y+4]^2=0.求代数式:3/2X+1-2/3Y-1.此题答案为2.2.已知A,B,C满足1/A+1/B+1/C不等于0,A(1/B+1/C)+B(1/A+1/C)+C(1/A+1/B)=-3,求A+B+C的值.此题答案为0.
1.若|(X-1)/(2X-3)|+[(3Y+1)/Y+4]^2=0.求代数式:3/2X+1-2/3Y-1.
此题答案为2.
2.已知A,B,C满足1/A+1/B+1/C不等于0,A(1/B+1/C)+B(1/A+1/C)+C(1/A+1/B)=-3,求A+B+C的值.
此题答案为0.
1.若|(X-1)/(2X-3)|+[(3Y+1)/Y+4]^2=0.求代数式:3/2X+1-2/3Y-1.此题答案为2.2.已知A,B,C满足1/A+1/B+1/C不等于0,A(1/B+1/C)+B(1/A+1/C)+C(1/A+1/B)=-3,求A+B+C的值.此题答案为0.
第一题,
(x-1)/(2x-3) = 0 => x=1
(3y+1)/y + 4 = 0 => y=-1/7
代数式可得解
第二题
设A+B+C = X
原代数式可拆为
A/B + A/C + B/A + B/C + C/A + C/B = -3
=> (A+C)/B + (A+B)/C + (B+C)/A = -3
=> (X-B)/B + (X-C)/C + (X-A)/A = -3
=> X/B -1 + X/C -1 + X/A -1 = -3
=> X(1/B + 1/C + 1/A) = 0
=> X = 0 (因为 1/A + 1/B + 1/C 不等于0)