在三角形ABC中,角ABC的对边分别为abc,且满足(2b-c)cosA-acosC=01.求角A的大小 2.若a=根号3,S三角形ABC=(3根号3)/4,试判断三角形ABC的形状,并说明理由
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![在三角形ABC中,角ABC的对边分别为abc,且满足(2b-c)cosA-acosC=01.求角A的大小 2.若a=根号3,S三角形ABC=(3根号3)/4,试判断三角形ABC的形状,并说明理由](/uploads/image/z/1603441-1-1.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ABC%E7%9A%84%E5%AF%B9%E8%BE%B9%E5%88%86%E5%88%AB%E4%B8%BAabc%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%282b-c%29cosA-acosC%3D01.%E6%B1%82%E8%A7%92A%E7%9A%84%E5%A4%A7%E5%B0%8F+2.%E8%8B%A5a%3D%E6%A0%B9%E5%8F%B73%2CS%E4%B8%89%E8%A7%92%E5%BD%A2ABC%3D%283%E6%A0%B9%E5%8F%B73%29%2F4%2C%E8%AF%95%E5%88%A4%E6%96%AD%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E5%BD%A2%E7%8A%B6%2C%E5%B9%B6%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
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