当x,y为实数,满足x²+3y²-12y+12=0求y^x
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当x,y为实数,满足x²+3y²-12y+12=0求y^x
当x,y为实数,满足x²+3y²-12y+12=0求y^x
当x,y为实数,满足x²+3y²-12y+12=0求y^x
x²+3(x²-4y+4)=0
x²+3(y-2)²=0
所以x=0,y-2=0
y=2
所以原式=2^0=1