已知x+y=1,则½x²+xy+½y²=
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已知x+y=1,则½x²+xy+½y²=
已知x+y=1,则½x²+xy+½y²=
已知x+y=1,则½x²+xy+½y²=
½x²+xy+½y²
=½(x²+2xy+y²)
=½(x+y)²
=½ ×1²
=½
原式=½(x²+2xy+y²)
=½(x+y)²
=½×1²
=½