分解因式:2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
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分解因式:2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
分解因式:2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
分解因式:2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
问题是不是提错了?
2x(x-y)²(x-y)²-x²(x-y)²+xy(y-x)²
=2x(x-y)²(x-y)²-x²(x-y)²+xy(x-y)²
=(x-y)²[2x(x-y)²-x²+xy]
=(x-y)²[2x(x-y)²-x(x-y)]
=x(x-y)²(x-y)(2x-2y-1)