作业帮已知x+y=3/2,xy=4/3,求x³y+2x²y²+xy³的值
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已知x+y=3/2,xy=4/3,求x³y+2x²y²+xy³的值
已知x+y=3/2,xy=4/3,求x³y+2x²y²+xy³的值
已知x+y=3/2,xy=4/3,求x³y+2x²y²+xy³的值
x³y+2x²y²+xy³
=xy(x²+2xy+y²)
=xy(x+y)²
=4/3*(3/2)²
=3
x³y+2x²y²+xy³
=xy(x^2+2xy+y^2)
=xy(x+y)^2
=4/3*9/4
=3
正确答案是3